Homework

9.13 A. Ho : u<42 Ho : u>42 B. z= 42.95-42/2.64/ square root of 65 = 0.95/0.33=2.87. .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha C. 1-0.9979=0.0021 .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha D. in that location is extremely ardent evidence 9.22 When scrutinying a hypothesis most populations mean to see whether to use a z test or a test simply comes down to whether o is cognise or not. If it is unknown you use a t test is it is known you use a z test. 12.10 A. It is withdraw to carry divulge a chi-square test using these selective information because it is gener everyy hold that n should be considered large if every of the expected carrel frequencies are at least 5. In this problem all of the Ei values are greater than or equal to 5. B.

I reason out that I cannot winnow out the pi values found in our problem, since it is much larger. 12.18 (a) A. I cogitate that I cannot eradicate the pi values found in our problem, since it is much larger. Depreciation method and country are cut back and the test is valid. You can see this because since the p-value is much greater than .05 we cannot reject the hypothesis of normality at the .05 level of significance.If you want to produce a full essay, order it on our website: OrderCustomPaper.com

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